SOLUTION: A boy throws a rock over the edge of a cliff. The rock is h feet above the boy after t seconds and is represented by function h=48t-16t^2. a. What is the height of the rock afte

Question 1022803: A boy throws a rock over the edge of a cliff. The rock is h feet above the boy after t seconds and is represented by function h=48t-16t^2.
a. What is the height of the rock after 2 seconds?
b. When is the rock 32 feet in the air?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A boy throws a rock over the edge of a cliff. The rock is h feet above the boy after t seconds and is represented by function h=48t-16t^2.
a. What is the height of the rock after 2 seconds?
h(t) = -16t^2 + 48t
Find h(2)
==============
b. When is the rock 32 feet in the air?
h(t) = -16t^2 + 48t
"In the air" ?? What does that mean?

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