SOLUTION: The winner of the track meet had an average speed of 5 meters per second. the second plae runner had an average speed of 4.5 meters per second. if the winner finished 2.2 seconds a

Question 102249: The winner of the track meet had an average speed of 5 meters per second. the second plae runner had an average speed of 4.5 meters per second. if the winner finished 2.2 seconds ahead of the second place runner, how long did it take the winner to cross the finish line?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
5m/s
4.5m/s
d=st d=distance s=speed t=time
st=st
5t=4.5(t+2.5)
5t=4.5t+11.25
.5t=11.25 subtract 4.5t from each side.
t=11.25/.5 divide each side by .5
t=22.5 sec. Ans
Check:
5*22.5=112.5 m (dist of race)
4.5(22.5+2.5)=4.5*25=112.5 m
Ed

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