SOLUTION: Solve- 7e^3x + 5 = 40 * round to the nearest thousandth * must be an algebraic solution

SOLUTION: Solve- 7e^3x + 5 = 40 * round to the nearest thousandth * must be an algebraic solution

Algebra.Com

Question 1022326: Solve- 7e^3x + 5 = 40
* round to the nearest thousandth
* must be an algebraic solution
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Take the natural log of both sides

----------------
check:

error due to rounding off
RELATED QUESTIONS
Solve: 7e^3x + 5 = 40 * round to the nearest thousandth * only algebraic solution will... (answered by Alan3354,MathLover1,MathTherapy)

Solve: (2)7^x=26 * must be an algebraic solution * round to the nearest... (answered by Alan3354)

1. Solve. -6x + 3 - 2x = 3 - 8x A) x = -16/3 B) Infinitely many solutions C) x =... (answered by Fombitz)

solve for x and round to nearest ten-thousandth 6^(3x)... (answered by josgarithmetic,MaxWong)

Solve. Round results to the nearest thousandth.... (answered by Ave,Waleak)

Solve for x. Round to the nearest ten-thousandth. 6^(3x+8) =... (answered by Alan3354)

Solve 3log2x=4. Round to the nearest... (answered by josmiceli)

Solve 10^6x = 93. Round to the nearest... (answered by jim_thompson5910,Alan3354)

Solve ln(5x + 7) = 8. Round to the nearest thousandth. (answered by MathLover1)