SOLUTION: cost of producing x cars per week is C(x)=1000+400x-0.1x^2 what is the marginal cost at x=300?

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Question 1021070: cost of producing x cars per week is C(x)=1000+400x-0.1x^2
what is the marginal cost at x=300?

Found 3 solutions by MathLover1, robertb, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!


the marginal cost at will be:




Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
The marginal cost function is simply the derivative of the total cost function.
==> MC(x) = 400 - 0.2x
==> MC(300) = 400 - 0.2*300 = 340.

Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!
cost of producing x cars per week is C(x)=1000+400x-0.1x^2
what is the marginal cost at x=300?
Marginal cost: 1st derivative of function, so  becomes: 
Marginal cost: -------> M(300) = 400 - 60, or
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