SOLUTION: Solve for a
Mgsin(theta)-f=ma; f=Ia/r^2
My answer: mg(sin(theta))/((I/r^2)+m)= a
Answer supposed to be (gsin(theta))/(1+I/r^2)= a
Algebra.Com
Question 1015488: Solve for a
Mgsin(theta)-f=ma; f=Ia/r^2
My answer: mg(sin(theta))/((I/r^2)+m)= a
Answer supposed to be (gsin(theta))/(1+I/r^2)= a
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Mgsin(theta)-f=ma; f=Ia/r^2
Is it 2 eqn or 2?
It's not clear.
--------
Mgsin(theta)- Ia/r^2 = ma
Mgsin(theta) = Ia/r^2 + ma
Mgsin(theta) = a*(I/r^2 + m)
a = Mgsin(theta)/(I/r^2 + m)
RELATED QUESTIONS
r^2sin2(theta)=a^2 (answered by greenestamps)
How to change r=1-sin theta a polar equation to rectangular form
i've started to solve (answered by jim_thompson5910)
z=r(cos theta + i sin theta) show:
a) {z}=r
b) 1/z = 1/r(cos theta - i sin... (answered by stanbon)
convert to a polar equation r+r sin... (answered by stanbon)
Simplify:
{{{ (sqrt (2) + sqrt (2) i )^3 }}}
The answer should be in the form of {{{... (answered by tommyt3rd)
Please help me answer this question: For all valuesof "theta", the expression... (answered by stanbon)
How to solve the following:
sin theta cot^2 theta sec ^2 theta = ?
Answers: a)sec... (answered by lwsshak3)
Which expression is equivalent to sin(2theta) for all values of theta?
2cos^2(theta) - 1
(answered by Boreal)
P(2,-5) is a point on the terminal side of the angle theta. Find the exact values of sin... (answered by jim_thompson5910)