SOLUTION: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half of the length. Find the length and width.

Question 1014838: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half of the length. Find the length and width.
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
Set w = width
l = length
w = 2 + (1/2)l
Perimeter = 2 widths plus 2 lengths
40 = 2*w + 2*l
Substitute ( 2 + (1/2)l ) for w in 40 = 2w + 2*l
40 = 2( 2 + (1/2)l ) + 2*l
40 = 4 + l + 2*l
40 = 4 + 3*l
add -4 to each side
36 = 3*l
divide each side by 3
12 = l
Substitute 12 for l in 40 = 2*w + 2*l
40 = 2*w + 2*12
40 = 2*w + 24
add -24 to each side
16 = 2*w
divide each side by 2
8 = w
Checking, the perimeter is 2*8 + 2*12 = 16 + 24 = 40
So we know the width is 8 and the length is 12
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