SOLUTION: Find a and b such that the zeros of ax^2 + bx +24 are 3 and 4.

Question 1014156: Find a and b such that the zeros of ax^2 + bx +24 are 3 and 4.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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equation with roots 3 and 4:
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To make c=24, we must multiply by 2.
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ANSWER: a=2 and b=-14
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CHECK:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=4 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 4, 3. Here's your graph:

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