SOLUTION: The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile,
The greatest height reached by the
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Question 1013069: The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile,
The greatest height reached by the projectile,
The time of flight,
The range of the projectile.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g=10m/s find;
The initial velocity of the projectile
= sqrt(6^2 + 8^2) = 10 m/sec
----------------
The greatest height reached by the projectile
h(t) = -10t^2 + 6t
h'(t) = -20t + 6 = 0 at max
t = 0.3 second
h(0.3) = 0.9 meters
-------------
The time of flight
= 2*tmax
= 0.6 seconds
------------------
The range of the projectile.
= 0.6*8
= 4.8 meters
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
.
The vertical and horizontal component of a projectile are 6m/s and 8m/s respectively take g = 10 m/s. Find
The initial velocity of the projectile
= sqrt(6^2 + 8^2) = 10 m/sec
----------------
The greatest height reached by the projectile
h(t) =
h'(t) = -10t + 6 = 0 at max
t = 0.6 second to get the greatest height.
h(0.6) = 1.8 meters
-------------
The time of flight
= 2*tmax
= 1.2 seconds
------------------
The range of the projectile.
= 1.2*8
= 9.6 meters
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