SOLUTION: Merry Christmas Tutors. @ problems below. A. Help Solve: y=(1/3) (x) -1 4x-3y=18, and graph the two equations and then identify the point where those two lines intersect.

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Question 1011345: Merry Christmas Tutors.
@ problems below.
A. Help Solve: y=(1/3) (x) -1 4x-3y=18, and graph the two equations and then identify the point where those two lines intersect.
B. Q#Amusement Park Admission
Cedar Park Amusement Park charges $51.99 for an adult admission and $26,99 for a junior admission. One Thursday the park collected $15.591.40 from a total of 360 adults and juniors. How many admissions of each type were sold?

Thank you, Betty


Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
A. Help Solve: y=(1/3) (x) -1 4x-3y=18, and graph the two equations and then identify the point where those two lines intersect.
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Two equations::
y = (1/3)x
y = (4/3)x - 6
------

-----
Ans: (6,2)
------------------------
B. Amusement Park Admission
Cedar Park Amusement Park charges $51.99 for an adult admission and $26,99 for a junior admission. One Thursday the park collected $15.591.40 from a total of 360 adults and juniors. How many admissions of each type were sold?
-----
Quantity Equation:: a + j = 360 tickets
Value Equation:: 51.99a + 26.99j = 1559140
---------------------------------
Modify for elimination::
5199a + 5199j = 5199*360
5199a + 2699j = 1559140
-----
Subtract and solve for "j":
2500j = 312500
j = 125 (# of junior tickets sold)
---
a = 360-125 = 235 (# of adult tickets sold)
-------
Cheers,
Stan H.
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Merry Christmas Tutors.
@ problems below.
A. Help Solve: y=(1/3) (x) -1 4x-3y=18, and graph the two equations and then identify the point where those two lines intersect.
B. Q#Amusement Park Admission
Cedar Park Amusement Park charges $51.99 for an adult admission and $26,99 for a junior admission. One Thursday the park collected $15.591.40 from a total of 360 adults and juniors. How many admissions of each type were sold?

Thank you, Betty
Duplicate. See Question 1011101 

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