SOLUTION: How do I identify the focus, directrix and axis of symmetry when y= -1/12x^2?
Algebra.Com
Question 1011138: How do I identify the focus, directrix and axis of symmetry when y= -1/12x^2?
Found 2 solutions by MathLover1, It is costly:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
we can see that the vertex will be at (,)=(,)
The standard form of a parabola (in this case upside down parabola) with a vertical axis of symmetry is
, where is the directed distance between the vertex and focus (and also between the vertex and directrix)
since and , we have
since you have , then
focus | (,)=(, )
p is the directed distance between the vertex and directrix, directrix will be units above x-axis :
Answer by It is costly(175) (Show Source): You can put this solution on YOUR website!
RELATED QUESTIONS
How do i identify the vertex, focus, and directrix of... (answered by Fombitz)
how to graph and identify the focus, directrix, and axis of symmetry of x=-y^2
(answered by lwsshak3)
How do I graph the equation x^2=-4y and identify the focus, directrix, and axis of... (answered by ewatrrr)
how do I find the Focus, Equation of the Directrix, and the equation of the axis of... (answered by stanbon)
How do I find the vertex, focus, directrix, axis of symmetry,
and latus rectum of this... (answered by Edwin McCravy)
Identify the vertex,the focus ,directrix ,axis of symmetry, and the latus rectum... (answered by lwsshak3)
Find the focus, directrix, vertex and axis of symmetry
x^2=1/8... (answered by MathLover1)
Identify the focus, directrix,and axis of symmetry of... (answered by josgarithmetic)
Identify the focus, directrix, and axis of symmetry of f(x)=1/16x^2. If possible please... (answered by josgarithmetic)