SOLUTION: h(t)=-16t^2+vt+h
if initial velocity is 64ft/s what is the max height
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Question 1010943: h(t)=-16t^2+vt+h
if initial velocity is 64ft/s what is the max height
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h(t)=-16t^2+vt+h
if initial velocity is 64ft/s what is the max height
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h(t)=-16t^2 + 64t
That's a parabola, and max ht is the vertex.
The vertex is at t = -b/2a = -64/-32 = 2 seconds
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h(2) = -16*4 + 64*2
= 64 feet
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