SOLUTION: find two consecutive positive integers such that the square of the first is increased by 17 equals 4 times these second a.what is the smaller number b.what is the bigger number

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Question 1008644: find two consecutive positive integers such that the square of the first is increased by 17 equals 4 times these second
a.what is the smaller number
b.what is the bigger number

Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
S=smaller integer=L-1; L=larger integer=S+1
.




Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -36 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -36 is + or - .

The solution is

Here's your graph:




Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -68 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -68 is + or - .

The solution is

Here's your graph:

.
ANSWER: There are no real number solutions,
regardless if you consider the larger or smaller
number as first.

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