SOLUTION: A person wishes to mix coffee worth $12 per lb with coffee worth $6 per lb to get 90 lb of a mixture worth $8 per lb. How many pounds of the $12 and the $6 coffees will be needed?

Question 1004583: A person wishes to mix coffee worth $12 per lb with coffee worth $6 per lb to get 90 lb of a mixture worth $8 per lb. How many pounds of the $12 and the $6 coffees will be needed?

Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
x+y= 90
Subtract x on both sides:
y= 90-x In the next equation we will substitute y with this value:
----------------------
We want to get 90lbs of coffee at $8 per pound, we want 90*8= 720:
12x+6y= 8(90) In this equation, substitute the value of y with 90-y:
--------------
12x+6(90-x)= 720
12x+540-6x= 720
6x= 180
x= 30
You need 30lb of $12 coffee with 90-30= 60 lbs of the $6 coffee
RELATED QUESTIONS
A person wishes to mix coffee worth $12 per lb with coffee worth $6 per lb to get 90 lb... (answered by fractalier)

I am having trouble setting up the problem/equations for this question... Deoraj Bharath... (answered by josgarithmetic)

A merchant has coffee worth $4 per lb. that she wishes to mix 50 pounds of coffee worth... (answered by richwmiller)

A merchant wishes to mix candy worth $5 per lb with 40 lb of candy worth $2 per lb to get (answered by ptaylor)

Sharon plans to mix peppermints worth $1.20 per lb with chocolates worth $2.40 per lb... (answered by addingup)

A merchant wishes to mix candy worth $5 per lb with 40lb of candy worth $2 per pound to... (answered by checkley75)

Why is it impossible to mix candy worth $4 per lb. and candy worth $5 per lb. to obtain a (answered by stanbon,josmiceli)

How many pounds of candy worth $8 per lb should be mixed with 100 lb of candy worth $4... (answered by Edwin McCravy)

a merchant has coffee worth $20a lb that she wishes to mix with 60 lbs of coffee worth... (answered by scott8148)