SOLUTION: Given the equation y= 1/2(x -5)^2 - 3 A write the equation in standard form b Write the equation in intercept form c find the x intercept(s) and the y intercept or explanin wh

Question 1002930: Given the equation y= 1/2(x -5)^2 - 3
A write the equation in standard form
b Write the equation in intercept form
c find the x intercept(s) and the y intercept or explanin why the intercepts do not exist
d. graph using the given form.
I really just need help with part b
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y= 1/2(x -5)^2 - 3
A write the equation in standard form
b Write the equation in intercept form
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Form:: y = a(x-b)(x-c)
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y = (1/2)(x^2-10x+25) - 3
I graphed it and found x-intercepts at x = 2.55 and 7.45
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y = a(x-2.55)(x-7.45)
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Solve for "a" using the y-intercept
y-intercept:
y = (1/2)(0-5)^2-3
y = 12.5-3 = 9.5
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y-intercept = (0,9.5)
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Solve for "a":
9.5 = a(-2.55)(-7.45)
a = 0.5
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Intercept Form::
y = 0.5(x-2.55)(x-7.45)
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Cheers,
Stan H.
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c find the x intercept(s) and the y intercept or explainin why the intercepts do not exist
d. graph using the given form.
I really just need help with part b
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