SOLUTION: I don't understand how to do this problem I have 3 like it please help asap thank you. My instructions say write an equation of the line that passes through point P and is parallel

Question 1002199: I don't understand how to do this problem I have 3 like it please help asap thank you. My instructions say write an equation of the line that passes through point P and is parallel to the line with the given instructions.... P(-3,6), y=-x-5
Found 2 solutions by jim_thompson5910, Boreal:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Given Line: y=-x-5
That is equivalent to y = -1x-5
The equation is in the form y = mx+b where the slope is m = -1

ANY line parallel to this given line will also have a slope of -1. Since parallel lines have equal slopes.

The given point is P(-3,6). All points are of the form (x,y) so x = -3 and y = 6

We will plug m = -1, x = -3 and y = 6 into y = mx+b and solve for b
-----------------------------------------

y = mx+b
y = -1x+b ... replace m with -1
y = -1(-3)+b ... plug in x = -3
6 = -1(-3)+b ... replace y with 6, solve for b
6 = 3+b
6-3 = 3+b-3 ... subtract 3 from both sides to isolate b
3 = b
b = 3

So we know m = -1 and b = 3 turning y = mx+b into y = -x+3 which is the final answer
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The line has slope -1, since it is written in slope-intercept form and x has a (-1) coefficient.
use point slope formula
y-y1=(-1)(x-x1)
y-6=(-1)(x+3)=-x-3
y=-x+3

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