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Tutors Answer Your Questions about Equations (FREE)
Question 240577: 6x-2-y=1
Answer by College Student(215)   (Show Source):
Question 240561: In one season, Kim ran 18 races. This was four fewer races than twice the number of races Kelly ran. How many races did Kelly run?
Answer by College Student(215) (Show Source):
You can put this solution on YOUR website!Hello!
.
If Kelly ran x number of races, we can then say Kim ran 2x-4=18.
So we now solve for x to determine how many races Kelly ran.
.
.
Since Kelly is x, she ran 11 races.
.
Let's check for Kim's number of races.
 ... it checks!
.
Done! :)
Question 241506: evaluate (-6c)^2 and 6c^2 when c = 10
Answer by stanbon(26296)  (Show Source):
You can put this solution on YOUR website!evaluate (-6c)^2 and 6c^2 when c = 10
-----
(-6c)^2 = (-6*10)^2 = (-60)^2 = 3600
-------------------------------
6c^2 = 6*(10)^2 = 6*100 = 600
================================
Cheers,
Stan H.
Question 241380: I need to factor 2x with exponent of 2 -4x-32=0
Answer by checkley77(7072) (Show Source):
You can put this solution on YOUR website!2x^2-4x-32=0
2(X^2-2X-16)=0
X=(2+-SQRT[-2^2-4*1*-16])/2*1
X=(2+-SQRT[4+64])/2
X=(2+-SQRT68)/2
X=(2+-8.246)/2
X=(10.246/2
X=5.123 ANS.
X=(2-8.246)/2
X=-6.246/2
X=-3.123 ANS.
Question 241466:
Found 2 solutions by jvurzua, stanbon:
Answer by jvurzua(1) (Show Source):
You can put this solution on YOUR website!Solve using the substitution method. First, solve one equation for one variable.
s + t = - 4,
s - t = 2
first we need to get single a single variable on one side of the equation, which is simpler in the second one.
subtract s from both sides and we get -t = 2-s
the we have to reverse the signs t = -2 + s so we have a positive value of T to substitue into the first equation. now we replace T in the first equation with -2+s
S + (-2 + S) = -4
-2 + 2s = -4
now we add 2 to each side to eliminate it single out the variable on the left side of the equation. (-2+2) + 2s = (-4+2)
2s = -2
now divide both sides by 2 to single out the variable on the left side of the equation. 2s/2 = -2/2
s = -1 Now that we haw a value for s we can check our work by substituting it into the original equations to see if it is true.
-1 + t = -4
t = -3
-1 + -3 = -4 True
S - T = 2
-1 - -3 = 2
-1 + 3 = 2 True
Hope this helps.
Answer by stanbon(26296) (Show Source):
You can put this solution on YOUR website!Solve using the substitution method. First, solve one equation for one variable.
s + t = - 4,
s - t = 2
--------------------
solve the 2nd for "s":
s = t+2
-------------------
Substitute into to 1st and solve for "t":
t+2 + t = -4
2t + 2 = -4
2t = -6
t = -3
------
Since s = t+2, s = -3+2 = -1
================================================
Solution:
t = -3
s = -1
==========================
Cheers,
Stan H.
Question 241381: Can someone please tell me what I did wrong, IF I did indeed do anything wrong?
This is the equation:
(4x/x-2) = x+ (8/x-2)
This is what I did to get my answer:
(4x/x-2) = x+ (8/x-2)
4x = x(x-2) + 8
4x =  - 2x + 8
-4x -4x
- 6x + 8
(x-4)(x-2)
Your help would be greatly appreciate, as I desperately need it!
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(3012) (Show Source):
You can put this solution on YOUR website!It's not absolutly clear what you're doing,
although you have the right idea
Multiply both sides by 
The solutions are
These are the values that make the equation true
But the problem is that division by  is not
allowed, so must be rejected
I'll test the solution
OK
Answer by Alan3354(6094)  (Show Source):
You can put this solution on YOUR website!(4x/x-2) = x+ (8/x-2)
This is what I did to get my answer:
(4x/x-2) = x+ (8/x-2)
4x = x(x-2) + 8
----------------
4x = x^2 - 2x + 8
x^2 - 6x + 8 = 0
(x-4)*(x-2) = 0
x = 4
x = 2 (2 causes the dreaded "Divide by 0" error, so reject it)
-----
I don't see how you did, but you got to the same place.
4x = - 2x + 8
-4x -4x
- 6x + 8
(x-4)(x-2)
Question 241433: 12(y-1)-4y=3(2y-2)+9y
can u solve this equation
Answer by jim_thompson5910(13794) (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is which approximates to  .
Question 241368: Perform the indicated operation. thanks
(42k^3 + 12^k2 + 18k) ÷ (6k)
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(3012) (Show Source):
Answer by stanbon(26296) (Show Source):
Question 241367: Factor completely. If the polynomial is prime, state this. thanks
48x^2 + 40xy - 48y^2
Answer by josmiceli(3012) (Show Source):
Question 241341: Solve using the principle of zero products. thank you
(21 - 0.8x)(5 - 0.4x) = 0
Answer by stanbon(26296) (Show Source):
You can put this solution on YOUR website!Solve using the principle of zero products. thank you
(21 - 0.8x)(5 - 0.4x) = 0
---
Since the product is zero, at least one of those factors
must be zero.
----------------
If 21-0.8x = 0
then 0.8x = 21
and x = 26.25
-----------------------
OR
---
If 5-0.4x = 0
then 0.4x = 5
and x = 12.5
==========================
Cheers,
Stan H.
Question 241342: Factor by grouping, if possible. thank you
x^3 + 3x^2 + 8x + 24
Found 2 solutions by unlockmath, Earlsdon:
Answer by unlockmath(121)  (Show Source):
You can put this solution on YOUR website!Hello,
Yes, it's possible. Let's take the first two terms
x^3 + 3x^2 which we can rewrite as:
x^2(x+3)
Now look at the next two terms:
8x + 24 Which we can rewrite as:
8(x+3) Here's the trick. Notice in the parenthesis we have x+3 so this can be rewritten as:
(x^2+8)(x+3)
To check this out multiply these two out and should come out the the original. x^3 + 3x^2 + 8x + 24
RJ Toftness
www.Math-unlock.com
Answer by Earlsdon(4900) (Show Source):
Question 241343: Solve the problem. If necessary, round to the nearest tenth.
On a sunny day, a tree and its shadow form the sides of a right triangle. If the hypotenuse is 35 m long and the tree is 28 m tall, how long is the shadow?
Answer by checkley77(7072) (Show Source):
Question 241344: Multiply. thank you
(xy + 3)(8xy - 2)
Answer by checkley77(7072) (Show Source):
Question 241275: (x-1/x)=5 find the value of x2+1/x2=? here i wrote x square not x 2 please note that.Thanks
Answer by rapaljer(3622) (Show Source):
You can put this solution on YOUR website!If (x-1/x)=5, then square both sides and get this:
Add +2 to each side:
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240367: 3(x-3)=4x-11
Answer by College Student(215) (Show Source):
You can put this solution on YOUR website!Steps:
a. Multiply 3 by the contents of the parenthesis.
b. Group like terms on either side of the equation, such as the x terms are on one side of the equation and the integers are on the other.
c. Solve for x.
.
Problem:
Deduct 3x from both sides of equation. I chose to put the x on the right side in order to keep the variable positive. (It is also less confusing for many students)
 ...same as to say... 
.
Done! :)
Question 241254: 4(3-m)=5(2m+1)
Answer by jim_thompson5910(13794) (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Distribute.
 Subtract from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
Question 240985: three times one number plus -7 times another number equals 21
Answer by ankor@dixie-net.com(6693)  (Show Source):
You can put this solution on YOUR website!three times one number plus -7 times another number equals 21
:
3x + -7y = 21
:
3x - 7y = 21
:
-7y = -3x + 21
:
Multiply by -1
7y = 3x - 21
:
y =  x - 
y = x - 3
:
Some integer values, ignoring 0;
x=14, y=3
x=21 y=6
x=28 y=9
x=35 y=12
note as x increases by 7, y increase by 3
Question 241107: Factor completely, if a polynomial is prime state this: thank you
2t^2-7t-4
Answer by vleith(1977) (Show Source):
Question 241067: How do we solve 2q^3 - 8q^2 - 4950 = 0?
Answer by vleith(1977) (Show Source):
You can put this solution on YOUR website!I don't know any easy way to work this other than 'trying' all the factors.
Divide thru by 2 and then grind out the various factors of 2475.
Or go here and have them give you the answer --> http://www.wolframalpha.com/input/?i=2q^3+-+8q^2+-+4950+%3D+0
Question 241030: Factor each polynomial completely.
a^4 - ab^3 =
This is what I tried and I am not sure it is correct?
a^2a^2/a^2b^1 = a^2/b^1 I don't think this is the correct formula but I am not sure. Any help would be really appreciated.
Answer by rapaljer(3622) (Show Source):
You can put this solution on YOUR website!The first step in factoring is to try to take out any common factors. In this case, you have a common factor of a, so take out the "a" factor.
a^4-ab^3
a(a^3 -b^3)
Now, this is a DIFFERENCE OF CUBES. There is a special formula for this in the form of a BINOMIAL times a TRINOMIAL. You may want to see my website for additional explanation of this formula. See the note at the end of this problem.
a(___)(_________)
a(a-b)(________)
a(a-b)(a^2+ab+b^2)
To find my website, do a "BING" or a "GOOGLE" search for my last name "Rapalje". Near the top of the search list, you should see "Rapalje Homepage." Click on this, and look near the top of my homepage for the link "MATH IN LIVING COLOR". Choose "Intermediate Algebra", and look in "Chapter 2" for "Section 2.01, Factoring." This is my own explanation especially written for students who have trouble understanding math. I wrote this to students, NOT mathematicians, and I think you will find it easier to understand than your own traditional textbooks!! In addition to this page, the entire website is supported by my "MATH IN LIVING COLOR" pages, where the hardest problems are solved IN COLOR.
In addition, I have a video of me teaching this topic in the classroom a few years ago. To see this FREE video, from my Homepage, look for "Rapalje Videos in Living Color". Select "Intermediate Algebra", and look for "Factoring."
If you like my website, please recommend it to family and friends who have trouble understanding math!! It's ALL FREE!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240848: please help me solve 2/A = 3A/(5A-14)
Answer by checkley77(7072) (Show Source):
You can put this solution on YOUR website! 2/A = 3A/(5A-14) CROSS MULTIPLY.
3A^2=2(5A-14)
3A^2=10A-28
3A^2-10A+28=0
A=(10+-SQRT[-10^2-4*3*28])/2*3
A=(10+-SQRT100-336)/6
A=(10+-SQRT-236)/6
A=(10+-15.36i)/6
A=(10/6+-15.36i/6
A=1.667+-2.56i ans.
Question 240788: What is y in this equation 3/2y - y =4 + 1/2?
Answer by Alan3354(6094) (Show Source):
You can put this solution on YOUR website!3/2y - y =4 + 1/2
I'll assume you mean (3/2)y for the 1st term.
y/2 = 9/2
y = 9
----------
It could be 3/(2y), which would make a difference. Parentheses are free, use some.
Question 240757: Solve for x and y.
4x+9y=365
Answer by Alan3354(6094) (Show Source):
You can put this solution on YOUR website!4x+9y=365
----------
It's not possible. If you have 2 variables, you need 2 equations.
With only 1 eqn, you can find an infinite number of "solutions", eg:
x = 0, y = 365/9
x = 2, y = 119/3
x = 80, y = 5 etc
Question 240799: Write the equation of a circle with center at (-5, 2) and radius 5. Please help.
Answer by vleith(1977) (Show Source):
Question 240759: 3(x+2)=x-18. What does x equal?
Answer by edjones(3298)  (Show Source):
Question 240692: John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John?
Answer by nyc_function(260)  (Show Source):
You can put this solution on YOUR website!Did you try setting up a table to gather all the needed information?
Get back to me and show me what you have done and then we can take it from there.
Question 240686: Please help me out with this problem:
(1/x-4) + (4/4x-4) = 5/4
I don't know what the LCD would be, so I am unable to find the solution(s).
If you could please help me, it would be greatly appreciated!
Answer by Theo(675)  (Show Source):
You can put this solution on YOUR website!your equation is:
1/(x-4) + 4/(4x-4) = 5/4
factor out the 4 in 4/(4x-4) to get:
1/(x-4) + 1/(x-1) = 5/4
your common denominator is going to be (x-4)*(x-1)
multiply 1/(x-4) * (x-1)/(x-1) to get (x-1)/((x-4)*(x-1))
multiply 1/(x-1) * (x-4)/(x-4) to get (x-4)/(x-4)*(x-1)))
your equation becomes:
(x-1)/((x-4)*(x-1)) + (x-4)/((x-4)*x-1)) = 5/4
combine the two fractions with the common denominator to get:
((x-1) + (x-4)) / ((x-4)*(x-1)) = 5/4
simplify by combining like terms to get:
(2x-5)/ ((x-4)*(x-1)) = 5/4
multiply both sides of this equation by 4 to get:
(4 * (2x-5))/ ((x-4)*(x-1)) = 5
simplify by removing parentheses in the numerator on the left hand side of the equation to get:
(8x-20) / ((x-4)*(x-1)) = 5
multiply both sides of this equation by ((x-4)*(x-1)) to get:
8x-20 = 5 * ((x-4)*(x-1))
simplify by performing indicated operations and removing parentheses to get:
8x-20 = 5x^2 - 25x + 20
subtract 8x from both sides of the equation and add 20 to both sides of the equation to get:
0 = 5x^2 - 33x + 40 which is the same as:
5x^2 - 33x + 40 = 0
use the quadratic equation to solve this equation to get:
x = 5
or
x = 1.6
substitute for x in the original equation to confirm the result.
I did that and the results are confirmed so these values are your answer.
The quadratic formula is:
the standard form of the quadratic equation is:
ax^2 + bx + c = 0
your equation is:
5x^2 - 33x + 40 = 0
a = 5
b = -33
c = 40
plug those values into the quadratic formula and you get:
 which becomes:
 which becomes:
The result is x = 5 or x = 1.6
Question 240623: Bruce receives a weekly salart of $350. Hel also recieves a 6% commission on the total dollar volume of all sales he makes. What must his dollar volume be in a week, if he is to make a total of $710.?
Answer by checkley77(7072) (Show Source):
Question 240587: Solve and state properties
c) 2(3x-1)-5(2x+3)=4x-7
I know that distributive property has to take place but afterwards I don't know what to do.
thank you
Answer by rapaljer(3622) (Show Source):
You can put this solution on YOUR website!2(3x-1)-5(2x+3)=4x-7
6x-2-10x-15=4x-7
Next, combine like terms on the left side:
-4x-17=4x-7
Now, you need to get all the variable terms on one side and the number terms on the other side. It doesn't matter which side you get the variables on, but let's say you want ot get all the variables on the LEFT side. You need to get rid of the 4x on the right side, by subtracting 4x from each side:
-4x-4x-17=4x-4x-7
-8x-17=-7
Now, since you have all the variables on the LEFT side, you need to get all the NUMBER terms on the right side. To get rid of the -17, add a +17 to each side:
-8x-17+17=-7+17
-8x=10
Now, to "undo" the multiplication of x by -8, you must DIVIDE both sides by -8:
I have my own non-traditional explanation of this topic that you may find easier to understand than the one in your own textbook. To see my explanation of this important topic of EQUATION SOLVING, please see my own website! To find my website, do a "Bing" or "Google" search for my last name "Rapalje". Look for "Rapalje Homepage" near the top of the search list. Near the top of my Homepage, look for "Basic, Intermediate and College Algebra: One Step at a Time." In "Basic Algebra" look in Chapter 1 for "Section 1.08 Equation Solving." Most of these explanations are supported by my "MATH IN LIVING COLOR" pages in which the most difficult problems are solved IN COLOR.
I hope you will try it, and see what you think--it's all FREE!!
If you like my website, please recommend it to friends!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240544: Please help me solve using the substitution method
7x+3y=-25
-7x+y=29
Answer by unlockmath(121) (Show Source):
You can put this solution on YOUR website!Hello,
Let's take the second equation and get y alone. To do that we add 7x to both sides. That will give us:
y=7x+29 Now we can put this into the first equation:
7x+3(7x+29)=-25 Distribute and combine like terms we get:
28x + 87=-25 Now subtract 87 from both sides gives us:
28x = -112 Divide both sides by 28 gives us:
x = -4 To find y just plug -4 into either equation and we get:
y=1 To see if these are right plug both values into both equations and it should come out the same.
RJ Toftness
www.math-unlock.com
Question 240535: Please help me solve by the elimination method
x+3y=16
-x+8y=17
Answer by solver91311(5072)  (Show Source):
You can put this solution on YOUR website!
The strategy for solving by elimination is to find a multiplier for one or both of the equations such that you make the coefficient on one of the variables in one of the equations be the additive inverse of the coefficient on that same variable in the other equation.
In the case of given example, you don't have to find a multiplier for either equation because you already have a coefficient of 1 on x in the first equation and a coefficient of -1 on x in the second equation.
Just add the two equations, term-by-term. Since you will be adding x to -x, you will end up with 0x, effectively eliminating (hence the name of the method) that variable. The end result will be a single equation in one variable, in this case, y. Solve for the remaining variable, and then use this value to substitute back into either of the original equations in order to solve for the variable that you eliminated.
John
Question 240443: Solve the equation.
(y - 11) - (y + 6) = 8y
Answer by checkley77(7072) (Show Source):
Question 240455: i am doing a problem. here is the equation, x^2+8x i cant find out what this type of problem is called. like is it a ex. parabola?
Answer by Alan3354(6094) (Show Source):
Question 240430: what do you do if a minus sign is next to a parenthesis?
Answer by vleith(1977) (Show Source):
You can put this solution on YOUR website!Act like it is a "minus 1" and then distribute that across the values inside he parens
For instance
-(2x+3)
-1(2x+3)
-2x -3
get it?
Question 240364: Please help me understand the steps for solving this problem. The value of a two-digit number is twice as large as the sum of its digits. If the digits were reversed, the resulting number would be 9 less than 5 times the original number. Find the original number.
Answer by scott8148(3385)  (Show Source):
You can put this solution on YOUR website!let t="tens digit" and u="units digit"
"The value of a two-digit number is twice as large as the sum of its digits" ___ 10t + u = 2(t + u)
___ 10t + u = 2t + 2u
___ 8t = u ___ (there is only one pair of digits that works here)
"If the digits were reversed, the resulting number would be 9 less than 5 times the original number"
___ 10u + t = 5(10t + u) - 9
___ 10u + t = 50t + 5u - 9
___ 5u + 9 = 49t
substitute the value of u from the 1st part to find the value of t
___ then substitute t back to the 1st part to find the value of u
Question 238567: Solve by the elimination method.
4x-9y=6.5
7y-2x=-4.5
Answer by Alan3354(6094) (Show Source):
You can put this solution on YOUR website!4x-9y=6.5
7y-2x=-4.5 times 2 --> -4x+14y = 9
-------------
+4x -9y = 6.5
-4x+14y = 9
-------------- Add
5y = 15.5
y = 3.1
---------
4x - 9y = 6.5
4x - 9*3.1 = 6.5
4x = 34.4
x = 8.6
Question 240294: A= 1/2h (b1+b2 for b1 Please help,
solve the problem for the indicated letter
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(6094) (Show Source):
You can put this solution on YOUR website!A= 1/2h (b1+b2 for b1
------------
A right bracket is missing, I think it goes here:
A= 1/2h (b1+b2)
2A = h*(b1 + b2)
2A/h = b1 + b2
b1 = (2A/h) - b2
Answer by solver91311(5072) (Show Source):
Question 240283: hello my name is anthony and i need help with this problem cuz i am new at this and so here it is and explain it the best way you can step by step?
5(2x+3)=4(x-1)+1
Answer by rfer(2688) (Show Source):
You can put this solution on YOUR website!5(2x+3)=4(x-1)+1
10x+15=4x-4+1
subtract 15
10x+15-15=4x-4+1-15
10x=4x-18
subtract 4x
10x-4x=4x-4x-18
6x=-18
divide by 6
6x/6=-18/6
x=-3
Question 240293: Solve the formula for the indicated letter. thanks
P = s1 + s2 + s3 for s3 (Points :2)
Answer by solver91311(5072) (Show Source):
Question 240288: Solve using the addition and multiplication principles. thanks
-6r + 3 ≤ -3(4r - 9)
Answer by solver91311(5072) (Show Source):
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330
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