# SOLUTION: Divide 3x^3 - 5 by x - 1 and check

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 Click here to see ALL problems on Divisibility and Prime Numbers Question 63855This question is from textbook An Incremental Development : Divide 3x^3 - 5 by x - 1 and check This question is from textbook An Incremental Development Answer by ankor@dixie-net.com(15646)   (Show Source): You can put this solution on YOUR website!Divide 3x^3 - 5 by x - 1 and check : Using long division, Remember you have to have each degree of the equation represented, hence the 0x^2 + 0x inserted in the divided expression: (Using "...." to keep things lined up.) : .........................3x^2 + 3x + 3 ..........-------------------- (x-1)| 3x^3 + 0x^2 + 0x - 5 ............3x^3 - 3x^2 .............------------ ........................+3x^2 + 0x ........................+3x^2 - 3x ........................------------ ......................................+3x - 5 ......................................+3x - 3 .......................................------- ................................................-2 remainder : The quotient: 3x^2 + 3x + 3, remainder -2/(x-1) : You check by mult: (x-1) * (3x^2 + 3x + 3) you should get 3x^3 + 0 + 0 - 3, add the remaider of -2 and you will get the original expression