Tutors Answer Your Questions about Divisibility and Prime Numbers (FREE)
Question 95663: When using prime factorization method for finding the least common multiples, why are only certain prime number used instead of all prime numbers? How will I know what prime numbers to use?
6= 2.3
8= 2.2.2=2
LCM=2.2.2.3=24
What tells me to only use three of the four 2s?
Click here to see answer by stanbon(57410) |
Question 97845: Can you take me step by step in helping me with the prime factorization for the numbers 34, 37, 67, 123, and 71? I would love to learn how to do theses so that I may understand when testing time comes around.
Thank you.
Click here to see answer by coyote(32) |
Question 97923: Prove that n^3 + (n+1)^3 + (n+2)^3 is divisible by 9 for all n in Natural numbers. I have tried, let mathematical induction, let P(n) be the statement, then then n^9 - n is divisible by 9. I'm stuck...
Thanks
Click here to see answer by aaaaaaaa(138) |
Question 97923: Prove that n^3 + (n+1)^3 + (n+2)^3 is divisible by 9 for all n in Natural numbers. I have tried, let mathematical induction, let P(n) be the statement, then then n^9 - n is divisible by 9. I'm stuck...
Thanks
Click here to see answer by mathslover(135) |
Question 103551: Ok, I'm stumped. Divide the rational expressions.
x^4-x^3+x^2+x / x^3-4x^2+x-4 (these are the numerators)
2x^3+2x^2+x+1 / 2x^3-8x^2+x-4 (these are the denominators)
Here's what I have.
X(x^3-x^2+x)* 2x^2(x-4)+(x-4) nuerators
2x^2(x+1)(x+1) * x^2 (x-4)(x-4) denominators
now I'm stumped on factoring the first numerator
Click here to see answer by jim_thompson5910(28598) |
Question 105804: I don't know how to do this question.
Factor the monomial of the following.
8a2b,30x2y2, 45m3n2,84b2c3d.
The 2's and 3's are to the power, but I don't know how to display that on the computer. I don't know what monomial is, either.
Click here to see answer by checkley75(3666) |
Question 108477: Here is the problem that i CANNOT figure out :-(
Word problem:
Recently a very wealthy individual died and left a large amount of money to be distributed to two individuals. The problem was that this person did not tell anyone who these two people were. This rather cryptic message was left to help someone solve the mystery.
Social security numbers have 9 digits. Assuming there is a unique social security number for each person find the number that contains no 0's and the first number is divisible by 1, the first two numbers are divisible by 2, the first 3 numbers are divisible by 3 and so on - the entire number would then be divisible by 9. No digit is used twice.
There are two hints: The fifth number is a 5, AND there are no 0's.
Can you PLEASE help me?!
Thanks soooooo much, Samuel Urschel
Click here to see answer by ankor@dixie-net.com(15661)  |
Question 115654: I need help with these math problems on least common multiple.
20. 16,18
23. 4,17
26. 15,18
27. 12,14
28. 7,13
32. 3,5,12
33. 6,16,24
34. 12,18,24
Click here to see answer by jim_thompson5910(28598) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440
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