Prime factorization is unique except for the order of factors. n could only be 3 because (q^3*p^2)/r^2 = s^n then q^3*p^2= r^2*s^n There are 5 primes multiplied together on the left, so there must the same 5 primes multiplied together on the right. In fact p=r and q=s, and of course n=3. Edwin