SOLUTION: What is the least number that has 4 odd factors that are all the same? Each factor is greater than 1, and can have only 1 and itself as factors. Explain how you find the number.

Question 967849: What is the least number that has 4 odd factors that are all the same? Each factor is greater than 1, and can have only 1 and itself as factors. Explain how you find the number.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i'm not quite sure what you mean.
the factors can't be 1.
the factors have to be odd.
they have to be the same.
offhand i would say 3*3*3*3 would be equal to 9*9 = 81.
the number 81 has 4 odd factors that are all the same.
can't be 1 because 1 doesn't counts as a factor.
a prime number has 2 factors.
1 and itself.
every number has a factor of 1 and itself.
what makes a prime number different is that those are the only numbers.
1 is prime.
2 is prime because the only factors are 1 and itself.
3 is prime because the only factors are 1 and itself.
4 is not prime because the factors are 1 and itself and 2.
the factors themselves have to be prime is what i think you said.
3 meets that criteria.
it's odd.
it's prime.
4 of them are factors of 81 because 81 is equal to 3*3*3*3.
is that what you mean?

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