SOLUTION: I need help with this problem. The problem states: Two digits of this number were erased: 273*49*5. However we know that 9 and 11 divide the number. What is it? What I have

SOLUTION: I need help with this problem. The problem states: Two digits of this number were erased: 273495. However we know that 9 and 11 divide the number. What is it? What I have

Question 86869This question is from textbook Mathematics for elementary teachers
: I need help with this problem. The problem states:
Two digits of this number were erased: 273*49*5. However we know that 9 and 11 divide the number. What is it?
What I have done so far:
2+7+3+*+4+9+*+5 = 30+*+*
The only number divisible by both 9 and 11 is 99. However, to make the sum of this number equal 99 the two missing digits would have to be 35 and 34. Would these numbers be correct? I have tried other single digit numbers and haven't found a sum divided by both 9 and 11.
Your help would be appreciated. Thanks.
Sincerely
R. Franke This question is from textbook Mathematics for elementary teachers

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two digits of this number were erased: 273*49*5. However we know that 9 and 11 divide the number. What is it?
:
Here is one way you can do it, about 10 min on a calculator:
Last digit is a five, we have 3 factors: 11 * 9 * 5 = 495
:
Start on the high end, make the missing numbers both 9:
27394995/495 = 55343.424242
Strip off the decimal:
495 * 55343 = 27394785, (our highest multiply of 495 within this number)
:
Start with this number on a calc, subtract 495 until you read a number that
satisfies the statement
:
I used a Ti83 table, an equation of y = x-495. Table setup: start 27394785
Increment of -495, scrolled down looking at y; Got a value 27374985 after
scrolling down about 46 number. Missing numbers are 7 and 8
:
Check, using the given factors
27374985/9 = 3041665
27374985/11 = 2488635
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