SOLUTION: c(x)= 4x^2-368x+53 where c is cost and x is number of repairs how many watches must he repair to have lower cost?
a) 26 b) 53 c) 40 d) 46
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Question 865199: c(x)= 4x^2-368x+53 where c is cost and x is number of repairs how many watches must he repair to have lower cost?
a) 26 b) 53 c) 40 d) 46
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
c(x)= 4x^2-368x+53 where c is cost and x is number of repairs how many watches must he repair to have lower cost?
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You can solve for the minimum.
It's the vertex of the parabola.
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Or, you can find c(x) for each of the 4 values.
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