n^2 = 10*k+r 0 < r < 9 r is the units (last) digit of a perfect square Since 0²=0 1²=1, 2²=4, 3²=9 4²=16 5²=25 6²=36 7²=81 8²=64 9²=81 the last (units) digit of ALL perfect squares can only be 0,1,4,5,6, or 9. Thus r can be 0,1,4,5,6, or 9, r cannot be 2,3,7, or 8. 02 = 10(0) + 0 12 = 10(0) + 1 22 = 10(0) + 4 32 = 10(0) + 9 42 = 10(1) + 6 52 = 10(2) + 5 62 = 10(3) + 6 72 = 10(4) + 9 Edwin