SOLUTION: find the smallest square number that is divisible by 6, 18 and 21?

Algebra.Com
Question 789020: find the smallest square number that is divisible by 6, 18 and 21?
Answer by tommyt3rd(5050)   (Show Source): You can put this solution on YOUR website!
6=2*3
18=2*3^2
21=3*7
n=((2)(3)(7))^2=1764

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