SOLUTION: 125x^3+8y^3
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Algebra: Divisibility and Prime Numbers
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Question 55696
:
125x^3+8y^3
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tutorcecilia(2144)
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(a^3+b^3)=(a+b)(a^2+ab+b^2) [Use this pattern to factor the sum of two cubes]
125x^3+8y^3
[(5^3)(x^3)+(2^3)(y^3)][Factor]
(5x+2y)(25x^2+(2)(5)(xy)+4y^2)
(5x+2y)(25x^+10xy+4y^2)