SOLUTION: Factor by grouping, if possible, and check 8a3 &#8722; 2a2 + 12a &#8722; 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) (2a^2 + 3) + (4a - 1) The instructor says this

Algebra ->  Algebra  -> Divisibility and Prime Numbers -> SOLUTION: Factor by grouping, if possible, and check 8a3 &#8722; 2a2 + 12a &#8722; 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) (2a^2 + 3) + (4a - 1) The instructor says this       Log On

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 Algebra: Divisibility and Prime Numbers Solvers Lessons Answers archive Quiz In Depth

 Question 550397: Factor by grouping, if possible, and check 8a3 − 2a2 + 12a − 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) (2a^2 + 3) + (4a - 1) The instructor says this is wrong, but I don't understand why. All I was told is to check the last line. Help plz!!Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!Factor by grouping, if possible, and check 8a3 − 2a2 + 12a − 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) Factor out the (4a-1) to get: ------- (4a - 1)(2a^2+3) =================== Cheers, Stan H. =============