# SOLUTION: Find two integers such that: • both are odd • their sum is negative • their product is &#8722;135 • one is a perfect square • neither is a factor of the other

Algebra ->  Algebra  -> Divisibility and Prime Numbers -> SOLUTION: Find two integers such that: • both are odd • their sum is negative • their product is &#8722;135 • one is a perfect square • neither is a factor of the other       Log On

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 Click here to see ALL problems on Divisibility and Prime Numbers Question 434319: Find two integers such that: • both are odd • their sum is negative • their product is −135 • one is a perfect square • neither is a factor of the other Answer by solver91311(16868)   (Show Source): You can put this solution on YOUR website! We know that and from which we can derive Substitute Multiply by The square root of 135 is approximately 11 and 2/3. A perfect square in the vicinity of 11 is 9. 135 divided by 9 is 15. 9 is odd, a perfect square, not a factor of 15, and when multiplied by -15 (which is odd, not a perfect square, not a factor of 9) equals -135. Furthermore 9 + (-15) is negative. John My calculator said it, I believe it, that settles it