SOLUTION: what will be the remainder when 16^2+17^2+18^2+19^2 is divided by 70?
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Algebra: Divisibility and Prime Numbers
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Question 42047
:
what will be the remainder when 16^2+17^2+18^2+19^2 is divided by 70?
Answer by
fractalier(2101)
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You can
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I do not think there is a short cut...merely calculate...thus
16^2+17^2+18^2+19^2 =
256 + 289 + 324 + 361 = 1230
When you divide by 70, your remainder is 40.