SOLUTION: Add: 1/3 + 5/12 + 4/5

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To add you need to find a common denominator. In this case it is 60.
Hope this helps and feel free to contact me with further questions,
lyra
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Your Result: YOUR ANSWER Here's what you tried: Graphical form: simplifies to Text form: (1/3)+(5/12)+(4/5) simplifies to 31/20 Cartoon (animation) form: For tutors: simplify_cartoon( (1/3)+(5/12)+(4/5) ) If you have a website, here's a link to this solution. DETAILED EXPLANATION Look at . Remove unneeded parentheses around terms It becomes . Look at . Remove unneeded parentheses around terms It becomes . Look at . Remove unneeded parentheses around terms It becomes . Look at . Added fractions or integers together It becomes . Look at . Factors 93 and 60 have greatest common factor (GCF) of 3. Reducing fraction. It becomes . Result: Universal Simplifier and Solver Done!

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First Find a comon denonator. Which would be 60. so you now have: 20/60 + 25/60 + 48/60. Then We add. 93/60 is the answer. In lowsest terms it would be 1 11/20

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In order to ADD fractions, you must have a common denominator. This means a number that each of the denominators divides evenly into. You need to find a number that 3, 12, and 5 all divide evenly. One way to do this is to take MULTIPLES of the largest number, which is 12, and keep going until you find a number that can be also divided by 3 and 5. This means start with 12, 24, 36, 48, 60, etc. Did you see that 60 can be divided by 3 and 5?

Now, you need to change each fraction 1/3, 5/12, and 4/5 into fractions whose denominator is 60. To do this, the denominator 3 must be multiplied by 20, the denominator 12 must be multiplied by 5, and the denominator 5 must be multiplied by 12. It looks like this:




What this means is that you have:


Now add up all these numerators, and put the answer over the common denominator which is 60:



The fraction reduces since you can divide both 93 and 60 by 3:

This is an improper fraction, which is actually preferred in higher math, but in lower math they might want a mixed fraction. You may want to write this as


R^2 at SCC