Question 275093: Suppose n is divisible by 8 but not by 3. Then which of the following CANNOT be an integer?
A n/2 b n/4 c n d n/6
Found 2 solutions by Edwin McCravy, Theo: Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! Suppose n is divisible by 8 but not by 3. Then which of the following CANNOT be an integer?
A n/2 B n/4 C n D n/6
This problem is solved by this theorem:
If n is divisible by r, and r is divisible by s, then n is divisible by s.
The correct answer cannot be A, B, or C because of the above theorem
since 8 is divisible by 2, 4 and 1. (Note that n means n/1)
So that only leaves D. But let's see why n/6 CANNOT be an integer.
If n/6 were an integer, then n would have to be divisible by 3,
by the above theorem since 6 is divisible by 3. But this
contradicis the given statement that n is not divisible by 3. Thus
the assumption that n/6 is an integer is false.
Edwin
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! if n is divisible by 8, then it is also divisible by factors of 8.
since the factors of 8 are 2 and 4, then n would have to be divisible by 2 and 4 as well.
if n is divisible by 6, then it is also divisible by factors of 6.
since the factors of 6 are 2 and 3, then n would have to be divisible by 2 and 3 as well.
since it is not divisible by 3, then it is not divisible by 6 because 3 is a factor of 6.
n is always divisible by n.
your answer is selection d.
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