Suppose n is divisible by 8 but not by 3. Then which of the following CANNOT be an integer?
A n/2 B n/4 C n D n/6
This problem is solved by this theorem:
If n is divisible by r, and r is divisible by s, then n is divisible by s.
The correct answer cannot be A, B, or C because of the above theorem
since 8 is divisible by 2, 4 and 1. (Note that n means n/1)
So that only leaves D. But let's see why n/6 CANNOT be an integer.
If n/6 were an integer, then n would have to be divisible by 3,
by the above theorem since 6 is divisible by 3. But this
contradicis the given statement that n is not divisible by 3. Thus
the assumption that n/6 is an integer is false.
Edwin