SOLUTION: Fiona wants to buy a new house but she doesn't want a house with the numbers that are divisable by 3 or 5. If all the houses numbered between 100 and 150 inclusive are for sale how
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Question 265049: Fiona wants to buy a new house but she doesn't want a house with the numbers that are divisable by 3 or 5. If all the houses numbered between 100 and 150 inclusive are for sale how many houses can she choose from?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The multiples of 3 that are included in
houses numbered 100-150 are:
34 x 3 = 102
35 x 3 = 105
36 x 3 = 108
up to:
50 x 3 = 150
And the multiples of 5 are:
20 x 5 = 100
21 x 5 = 105
22 x 5 = 110
up to
30 x 5 = 150
------------
I don't want to count house numbers twice, so
in the 1st list I'll pull out thoses divisible by 5
35 x 3
40 x 3
45 x 3
50 x 3
------------
The 1st list has entries
I want to delete 4
The 2nd list has entries
There are 24 house numbers she doesn't want
possible numbers
She can choose from 27 houses
Hope I got it right!
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