SOLUTION: how do you get the factor form of n^2 - 3n -18

Algebra.Com
Question 263136: how do you get the factor form of
n^2 - 3n -18

Found 2 solutions by stanbon, drk:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
how do you get the factor form of
n^2 - 3n -18
---
(n-6)(x+3)
======================
Cheers,
Stan H.

Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
here we want 2 numbers that add to -3 and multiply to -18.
Since the product is - we must use a positive and a negative number.
listing the factor pairs of 18, we get
1, 18
2, 9
3, 6
Notice that if 3 were positive and 6 were negative, we get +3 -6 = -3 which is our middle number.
we now write 2 binomials as
(n - _____)(n - ______)
the blanks are waiting for our numbers +3 and -6. PUtting those in we get
(n+3)(n-6)

RELATED QUESTIONS

how do you do factor form like n^2 + 11n... (answered by drk)
how do you factor the equation... (answered by nikkiz)
how do you do factor form like n to the second power + 11n... (answered by stanbon,checkley77,dabanfield)
how do you factor... (answered by robertb)
How do you factor 3m^2-3n^2 I don't no how to start the... (answered by nyc_function)
How do you factor the expression 7n^5 + 7n^4 - 3n^2 - 6n -... (answered by sarah_adam)
What is the solution of the proportion? n-6= n-5 3n 3n+1 I cross multiplied and... (answered by josh_jordan)
Please help. How do I solve this? The sum of the first n terms is Sn= n/2 (3n-17). What... (answered by ssasr)
I am having trouble with solving rational equations! The problem is... (answered by scott8148)