SOLUTION: 93xy is divisible by 72. then, x= y= when this number is divided by 6,8,and 4, a there's always a reminder of 1?what is the least value of this number?

Algebra.Com
Question 238469: 93xy is divisible by 72. then,
x=
y=
when this number is divided by 6,8,and 4, a there's always a reminder of 1?what is the least value of this number?

Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
There is an error in the problem. Since 72 is divisible by 6, 8 and 4 and since 93xy is divisible by 72, 93xy must be divisible by 6, 8 and 4. There will be no (or zero) remainders.

Please correct and repost.

RELATED QUESTIONS

93xy is divisible by 72. then, x= y= (answered by vleith)
There is a number less than 3000 that when divided by 2 leaves a remainder of 1, when... (answered by ikleyn)
If N and M are the multiple of 2 which are not divisible by 4 then what will be the... (answered by edjones,richard1234)
1. Factorise: X^6 - 7X^3 - 8 2. Find the factor for X^2 + 5√2x + 12 3. If... (answered by ikleyn)
The polynomials (ax^3 + 3x^2 - 3) and (2x^3 - 5x + a) when divided by (x - 4) leaves the (answered by lwsshak3)
X is a number such that when ( x+1)² is divided by (X-2),the quotient is 16 and the... (answered by josgarithmetic)
Classify each of the following as true or false: (a) If a number is divisible by 6, then (answered by richwmiller)
when a polynomial P(x) is divided by 3x-4, the quotient is x^3+2x+2 and the reminder is... (answered by ikleyn)
what is the lowest number possible that when divided by 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 (answered by jim_thompson5910)