SOLUTION: Find a four digit number that is divisible by 3, 5, and 8.
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Question 181858This question is from textbook
: Find a four digit number that is divisible by 3, 5, and 8.
This question is from textbook
Found 2 solutions by nerdybill, solver91311:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
If you multiply all three numbers together:
3*5*8 = 120
.
Now, to get a four digit number, simply multiply by 10:
120 * 10 = 1200
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Multiply 120 by any integer in the range 
That's because 
, so you need the next higher integer to make sure you have at least 4 digits and, 
, so you need the next lower integer so that you make sure you have no more than 4 digits. Lastly, you don't care about the divisibility of this last factor because you have already ensured divisibility of the 120 factor by creating it from the product of the three given divisors.
In fact you could probably get extra credit for this question if you answered it by saying:
Meaning, the set of all x such that x and y are integers, x is equal to 120 times y and y is in the inclusive interval 9 to 83, which is a description of the set of all four-digit numbers evenly divisible by 3, 5, and 8.
John
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