Question 167662: let 5 be the set all intergers divisible by both 6 and 15 which of the following is not a divisor of every member of s 2,5,9
Answer by aaaaaaaa(138) (Show Source):
You can put this solution on YOUR website! A number, to be divisible by both 6 and 15, must be divisible by their least common multiple.
lcm(6, 15) = 30 = 2 * 3 * 5
Therefore all of the members of S are divisible by 2 or 5, but not necessarily by 9 (30 is an example).
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