# SOLUTION: I just want to double check to make sure I did this right. a. How many divisors does 5³ have? What are they? 5³ = 125 Divisors would be 1 , 5, 125 b. The prime factorizatio

Algebra ->  Algebra  -> Divisibility and Prime Numbers -> SOLUTION: I just want to double check to make sure I did this right. a. How many divisors does 5³ have? What are they? 5³ = 125 Divisors would be 1 , 5, 125 b. The prime factorizatio      Log On

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 Algebra: Divisibility and Prime Numbers Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Divisibility and Prime Numbers Question 166199This question is from textbook : I just want to double check to make sure I did this right. a. How many divisors does 5³ have? What are they? 5³ = 125 Divisors would be 1 , 5, 125 b. The prime factorization of a real number x is 3² * 11³. How many divisors does x have? List the divisors? What is the value of x? 3² = 9 Divisors would be 1, 3, 9 11³ = 1,331 Divisors would be 1, 11, 121, 1331 x = 9 * 1331 x = 11,979 This question is from textbook Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!1) How many divisors (factors) has ? The factors (divisors) of 125 are: 1, 5, 25, 125 2) The value of x = 11979. You are correct here. The factors (divisors) of 11079 are: 1, 3, 9, 11, 33, 99, 121, 363, 1089, 1331, 3993, 11979 Notice that if you multiply the first and last of the factors (1 * 11979 = 11979), you will get the starting number (11979). If you then multiply the second and next-to-last of the factors (3 * 3993 = 11979), again you get the starting number. Continue like this in pairs. 9*1331 = 11979 11+1089 = 11979 33*363 = 11979 99*121 = 11979 As you can see, there are many more than you thought!