SOLUTION: Find the smallest positive number that is divisible by 7 with a remainder of 4, divisible by 8 with a remainder of 5, and divisible by 9 with a remainder of 6.

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Question 122255: Find the smallest positive number that is divisible by 7 with a remainder of 4, divisible by 8 with a remainder of 5, and divisible by 9 with a remainder of 6.
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

If a zero quotient is acceptable, then the answers are 4, 5, and 6.
If the quotient must be at least 1 to qualify for your instructor's
definition of 'divisible', then the answers are:
7 + 4 = 11,
8 + 5 = 13,
and 9 + 6 =15.


The relationship is:


 where N is the number (also referred to as the dividend),
Q is the quotient, D is the divisor, and R is the remainder.


So for your first example:  N is what we want to determine, Q is either 0 or 1
depending on what 'divisible' means, D is 7, and R is 4.  Hence:


 or 


I'll let you work out the other two.



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