SOLUTION: Find the greatest prime divisor of the value of the arithmetic series 5 + 6 + 7 + \dots + 135.

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Question 1207597: Find the greatest prime divisor of the value of the arithmetic series
5 + 6 + 7 + \dots + 135.

Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52946)   (Show Source): You can put this solution on YOUR website!
.
Find the greatest prime divisor of the value of the arithmetic series
5 + 6 + 7 + \dots + 135.
~~~~~~~~~~~~~~~~~~~~~~~

This sum, as for any arithmetic progression, is the product of the mean by the number of terms.


The mean is   =  = 70.

The number of terms is  135-4 = 131.


So, the sum is  70*131.


Decomposition of the sum to product of primes is  70*131 = 2*5*7*131.


The greatest prime divisor is 131.


ANSWER.  The greatest prime divisor is 131.

Solved.

---------------

It's like a morning workout for the brain.




Answer by Edwin McCravy(20067)   (Show Source): You can put this solution on YOUR website!
It's interesting that the greatest prime divisor of the sum happened to turn out
to be the same as the number of terms, 135-5+1=131.  

It's further interesting that the greatest prime term of the series is also 131. 
[Note that 133 is not prime since 133=7x19].

[Some more workout for the brain. lol]

Edwin


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