Last digits ofform the sequence n 1 2 3 4 5 . . . last digits of 7 9 3 1 7 . . . This sequence is periodic with the period length of 4. How many periods of the length 4 are in the sequence 1, 2, 3, 4, . . . , 72 ? The number of periods is exactly = 18, so the last digit of the number is 1. ANSWER. has the last digit 1.
7^1 final digit 7 7^2 final digit 9 (7*7 = 49) 7^3 final digit 3 (9*7 = 63) 7^4 final digit 1 (3*7 = 21) 7^5 final digit 7 (1*7 = 7) ...