SOLUTION: Ok, I'm stumped. Divide the rational expressions. x^4-x^3+x^2+x / x^3-4x^2+x-4 (these are the numerators) 2x^3+2x^2+x+1 / 2x^3-8x^2+x-4 (these are the denominators) Here's

Question 103551: Ok, I'm stumped. Divide the rational expressions.
x^4-x^3+x^2+x / x^3-4x^2+x-4 (these are the numerators)
2x^3+2x^2+x+1 / 2x^3-8x^2+x-4 (these are the denominators)
Here's what I have.
X(x^3-x^2+x)* 2x^2(x-4)+(x-4) nuerators
2x^2(x+1)(x+1) * x^2 (x-4)(x-4) denominators
now I'm stumped on factoring the first numerator
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression

Multiply the first fraction by the reciprocal of the second fraction

Factor out an x out of the first numerator

Factor the first denominator through the use of factoring by grouping

Factor the second denominator through the use of factoring by grouping

Cancel like terms

Simplify

Since this expression cannot be simplified or factored further, this is our answer
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