Questions on Algebra: Divisibility and Prime Numbers answered by real tutors!

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Tutors Answer Your Questions about Divisibility and Prime Numbers (FREE)


Question 567583: The positive integer N has exactly eight different positive integral factors. Two of these factors are 15 and 21. What is the value of N?
Answer by richard1234(4789) About Me  (Show Source):
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Note that 15 = 3*5 and 21 = 3*7. The LCM of 15 and 21 is 3*5*7 = 105, however this already has eight factors (use the algorithm for finding the # of factors of a number, add 1 to each exponent, multiply). Therefore N = 105.


Question 566460: Hey I am having problems with this just Prime Numbers what are all the prime numbers?
Answer by richard1234(4789) About Me  (Show Source):
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Any integer greater than 1 that is only divisible by 1 and itself.

E.g. 2, 3, 5, 7, 11, 13, 17, ..., infinitely many primes.


Question 565188: i am a multiple of 5. two is not one of my factors. i am not prime and i am not square. i am less than 30. what number am i?

Answer by jim_thompson5910(21667) About Me  (Show Source):
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Multiples of 5 less than 30: 0, 5, 10, 15, 20, 25

Since 2 is NOT a factor, we cross out 0, 10, and 20


So we're left with: 5, 15, 25

The number is NOT prime, so 5 is out. The number is NOT a square, so 25 is also out.


So the answer is 15.


Question 563311: Your task is to find two different numbers that sum to 1000 . One number must be a multiple of 19 and the number must be a multiple of 47 . Show or explain how you got your answer .
Answer by richard1234(4789) About Me  (Show Source):
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19a + 47b = 1000

Solving for a,



We want 1000-47b to be congruent to 0 mod 19. Since 1000 is 12 mod 19, 47b must be 12 mod 19. Also, 47 is congruent to 9 (mod 19), so we have



If b = 14, then 9b = 126 which is 12 mod 19, so this works. Hence 47b = 47*14 = 658, 19*18 = 342. If you know Diophantine equations you can use this solution to generate infinitely many solutions.


Question 560364: A square has area 18225 square feet. What is the perimeter of the square. Could you please how me a step by step how to complete this problem
Answer by Earlsdon(6098) About Me  (Show Source):
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If the area of a square is 18225,the length of one side (s) is:
s+=+sqrt%2818225%29+=+135
The perimeter p is 4(s), so...
p+=+4%28135%29
p+=+540


Question 558849: REMOVED FOR LANGUAGE
Answer by KMST(576) About Me  (Show Source):
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DO NOT POST SUCH FILTH IN HERE.


Question 557800: What is the smallest number that can be divided by all the numbers 1 to 10?
Answer by Edwin McCravy(6931) About Me  (Show Source):
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Let the number be N

 1 = 1     so N must have factor 1 (every integer has factor 1, so we can ignore 1)
 2 = 2     so N must have factor 2
 3 = 3     so N must have factor 3
 4 = 2*2   so N must have factor 2*2  
 5 = 5     so N must have factor 5
 6 = 2*3   so N must have factor 2*3
 7 = 7     so N must have factor 7
 8 = 2*2*2 so N must have factor 2*2*2
 9 = 3*3   so N must have factor 3*3
10 = 2*5   so N must have factor 2*5

So the smallest N can be and have at least as many of 
every factor above is the product of three 2's, two 3's, 
one 5, and one 7, which means

N = 2*2*2*3*3*5*7 = 2520

Edwin


Question 553709: How to solve this problem 5\9of450
Answer by prateekagrawal(47) About Me  (Show Source):
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just we need to multiply 5/9 to 450.
so,
5/9 of 450= 5%2F9+%2A+450+=+5%2A50+=+250
so, 250 is the answer.


Question 553497: Find the greatest common divisor of 96 and 54.
Find the least common multiple of 30 and 42.

Answer by nyc_function(2626) About Me  (Show Source):
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Greatest Common Factor: The highest number that divides exactly into two or more numbers. It is the "greatest" thing for simplifying fractions!
What is the BIGGEST number that evenly divides 54 and 96?

How about 6?

54/6 = 9

96/6 = 16

Yes, that's correct.

The least common multiple (LCM) of two numbers is the smallest number (not including zero) that is a multiple of both.

Multiples of 3O: 30, 60, 90, 120, 150, 180, 210

Multiples of 42: 42, 84, 126, 168, 210

On the list provided, what number is found in both?

The number 210 is found in both.

Then 210 is the LCM.







Question 513810: FIND AL NUMBERS LESS THAN 50THAT ARE PRIMES AND HAVE A REMAINDER OF 3 WHEN THEY ARE DIVIDED BY 7.
Found 2 solutions by MathTherapy, JBarnum:
Answer by MathTherapy(638) About Me  (Show Source):
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FIND AL NUMBERS LESS THAN 50THAT ARE PRIMES AND HAVE A REMAINDER OF 3 WHEN THEY ARE DIVIDED BY 7.

Multiply all numbers, from 1 to 6, by 7, and than add 3 to see if the result is a prime number.

N.B. Multiplying 7 by 7, and adding 3 would yield 52 (7*7 + 3), which would be too large

_7 * 1 = 7 + 3 = 10 (NOT PRIME)
7 * 2 = 14 + 3 = 17 (PRIME)
7 * 3 = 21 + 3 = 24 (NOT PRIME)
7 * 4 = 28 + 3 = 31 (PRIME)
7 * 5 = 35 + 3 = 38 (NOT PRIME)
7 * 6 = 42 + 3 = 45 (NOT PRIME)
7 * 7 = 49 + 3 = 52 (NOT PRIME, and as stated above, 52 > 50)

Therefore, the numbers being sought are highlight_green%2817%29 and highlight_green%2831%29

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com

Answer by JBarnum(1826) About Me  (Show Source):
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list all primes up to 50
1 2 3 5 7 11 23 29 31 37 41 43 47
1-7 easily cancel out
11 23 29 31 37 41 43 47
./.../.../...(31).../.../.../.../
7*4=28 28+3=31


Question 493228: What are the two smallest numbers with only 10 divisors?
Answer by JBarnum(1826) About Me  (Show Source):
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100
1 100
2 50
4 25
5 20
10 10
__________
90
1 90
2 45
3 30
5 18
9 10
_____________
80
1 80
2 40
4 20
5 16
8 10

____________
80,90 the 2 lowest i found


Question 539852: How many integers between 1 and 200 are multiples of both 3 and 5 but not of either 4 or 7?
Answer by JBarnum(1826) About Me  (Show Source):
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use the 3 trick when counting with 5s starting at 15 1+5=6 so its divisible by 3
15,30,45,60,75,90,105,120,135,150,165,180,195
above are the possibilities for 3 n 5 but some are divisible by 4 and 7 so go through and knock those out
15,30,45,cross%2860%29,75,90,cross%28105%29,cross%28120%29,135,150,165,cross%28180%29,195


Question 541225: Separate 75 into two numbers so that the sum of the two numbers equals 75. Three times the smaller number is five more than the larger number.
Answer by JBarnum(1826) About Me  (Show Source):
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x+y=75
3x=y+5
3x-5=y
x+3x-5=75
4x=80
x=20
75-20=55
y=55


Question 541813: What multiplied by what equals 174?
Answer by JBarnum(1826) About Me  (Show Source):
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1 times 174=174
2*87=174
3*58=174
6*29=174


Question 543666: what is the largest 5 digit number that is divisible by 3
Answer by JBarnum(1826) About Me  (Show Source):
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99999
9 is divisible by 3 so 99999 is the greates 5 digit number


Question 551436: Model each expression:
(t devided by 2) -4
How do you write this
Action 1
Action 2
We r confussed for thi and the next one which is subtraction
The example is (m x 4) + 7
Action 1 was 4 boxes with an m in each and action 2 is + 6

Answer by JBarnum(1826) About Me  (Show Source):
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%28t%2F2%29-4
4m%2B7
action boxes?? no idea what those are
im assuming its like 5 x []=10 where the "box" represents 2 but i have never seen boxes in algebraic expressions


Question 552210: What is the smallest number that has a remainder of 0 when divided by 16 and 36? I have listed the multiples of these two numbers out to see if they have a LCM, but I cannot seem to find one. I know that you can multiply if the two numbers are prime numbers to solve, but in this case they are not. Please help! I need this by tomorrow!
Answer by jim_thompson5910(21667) About Me  (Show Source):
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GCF of 16 and 36 is 4

LCM = 16*36/(GCF) = 576/4 = 144

So the LCM of 16 and 36 is 144


Question 551088: what are the steps and answer to 450 divided by 270
Answer by AnlytcPhil(1116) About Me  (Show Source):
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450 divided by 270

Here are two ways:

First way:

      1 
270)450
    270
    180

1%26180%2F270 = 1%2618%2F27 = 1%262%2F3

Second way:

450%2F270

Since both end with a 0, they can both be divided by 10, so:

%27450%F710%27%2F%27270%F710%27

To divide by 10, just drop off the 0's on the end and you get

45%2F27

Now if we remember our 9's multiflication facts, we
remember that 5×9 = 45 and 3×9 = 27, so

%2745%F79%27%2F%2727%F79%27

and you get

5%2F3

Then you change that to a mixed number and get:

1%262%2F3

Edwin


Question 550550: if u go to the following website, it has the act practice science test. I need help on the following questions from the page and these questions are from the act practice booklet. I don't know how act got these answers so much help would be appreciated with showing work.
i don't know how it got the answer for the following questions on this science section.
3. d
4. f
6. f
7. c
8. j
10. j
https://docs.google.com/viewer?a=v&q=cache:IJcWZIWzbI4J:shsbio1.wikispaces.com/file/view/ACTScience.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESgjG6eGKED4dPd_CalM01gYk5fzPTrRWwUUe9OiiNIdK2CxJbyJmsWLHep07LEBkpgCnT0GjsBHoUHbjFc_Wedy5bOGGXGFfQ_r9NBqxEqtqzBPEPuiiHKlu-HFH55fQ4Pbop1_&sig=AHIEtbTtW8bDP48r2gGb2PrvuC93B1J4_A
thanks for ur help and god bless you.

Answer by fcabanski(385) About Me  (Show Source):
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ACT science is about finding stuff in charts, graphs and sometimes in blurbs. The stuff just happens to be sciencey. You don't have to know the science to answer the questions. You just have to read the information.


If you're confused with science, or just want to raise your score in general, I tutor ACT prep. Drop me a line.
3 - look at figure 3. The difference in times for p waves and s waves to reach the seismograph is increasing as distance from earthquake to seismograph increases. At 10,000 km it's somewhere around 12 minutes, so for 10,500 km it's certainly at least 12. Those lines are not going to suddenly converge. The only valid answer is d.


4 - Examine figure 2 and figure 3. The earthquake begins, then those waves move and are detected by the seismographs at different distances from the focus. Figure 3 begins at 0 km distance from the focus, 0 minutes after the earthquake. That's when the earthquake happens, or starts at the focus. The answer is f.


6 - Examine figure 2. Note that the top color is lake clay, and its height shows elevation which is also the thickness of that layer. Where is the top color thinnest? The answer is at Winnepeg Manitoba.


7 - Examine figure 3. The smallest oxygen isotope ratio is at the left of each site chart. It shows that at the top (smaller ----------> larger). In each case, it's between 20 and 30 m. That's c.

8 - The top gray layer is the lake clay. The second layer, with the diagonal lines, is glacial till. Clay gets wider/thicker moving left from Grand Forks to Site 3. The glacial till gets thinner moving left from Gran Forks to Site 3. It's decreasing. That's J.


10 - For all three sites the y-axis is depth. 3M is the right most dot in each table. It's at about -15 in each case. That's J.


Keep in mind I tutor ACT prep via Skype online. This includes strategies and subject matter prep in each area. There is no subject matter prep in science. All the information is contained in the tables and charts and graphs, and in the passages. You just have to find it when answering the questions.



Question 550489: Factor the expression 49x^2-42xy+9b^2
I got the answer (7x-3y)(7x-3y), something tells me this is wrong however. I've worked on it for the last 3 hours now and just need some help I guess.

Found 2 solutions by scott8148, Edwin McCravy:
Answer by scott8148(5879) About Me  (Show Source):
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if the expression is written correctly, it is not factorable

if it is this "49x^2-42xy+9y^2"' then your factors are correct

if it is this "49x^2-42xb+9b^2"' then the factors are ___ (7x-3b)(7x-3b)

Answer by Edwin McCravy(6931) About Me  (Show Source):
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(7x-3y)(7x-3y) is correct except there is one more step.
Since both factors are the same, you can write that simpler as
(7x-3y)˛


Question 550397: Factor by grouping, if possible, and check
8a3 − 2a2 + 12a − 3
(8a^3 - 2a^2) + (12a - 3)
2a^2(4a - 1) + 3(4a - 1)
(2a^2 + 3) + (4a - 1)
The instructor says this is wrong, but I don't understand why. All I was told is to check the last line. Help plz!!

Answer by stanbon(48510) About Me  (Show Source):
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Factor by grouping, if possible, and check
8a3 − 2a2 + 12a − 3
(8a^3 - 2a^2) + (12a - 3)
2a^2(4a - 1) + 3(4a - 1)
Factor out the (4a-1) to get:
-------
(4a - 1)(2a^2+3)
===================
Cheers,
Stan H.
=============


Question 550249: Factor completely Please show work as I am not sure how to do this.
9t2 + 14t + 5

Answer by Alan3354(21550) About Me  (Show Source):
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Factor completely Please show work as I am not sure how to do this.
9t2 + 14t + 5
-------------
It will be (at + b)*(ct + d)
b*d = 5
--> (at + 1)*(bt + 5)
Find integers for a & b so that a*b = 9 and 5a + b = 15
It's trial and error with only a few possibilities.
-----
For a & b, it's either 1*9 or 3*3
==========
There's nothing to be gained by me doing it.


Question 550256: classify the number as prime, composite, or neither
10

Answer by Alan3354(21550) About Me  (Show Source):
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Hint: All even numbers have a factor of 2.


Question 550084: The radio signal from the transmitter site of radio station WGGW can be received only within a radius of 52 miles in all directions from the transmitter site. A map of the region of coverage of the radio signal is shown be low in the
standard (x,y) coordinate plane, with the transmitter site at the origin and 1 coordinate unit representing 1 mile.
i don't know how to do a graph on here as there also is a graph to do these 3 problems. There is a circle, then a vertical and horizontal line crossing and where the intersect, there is like a 0 sort of. Then from that 0 to the y axis up is 52 and to the x axis on right is 52 too. So hope this helps, sorry i couldn't draw a graph for an easier way to do this problem.
54. Which of the following is closest to the area, in square miles, of the region of coverage of the radio signal? the answer is j but how did it get that so work would be much appreciated.
F. 2,120
G. 2,700
H. 4,250
J. 8,500
K. 16,990
55. Whi ch of the fol lowing i s an equa t ion of the c i r c l e
shown on the map? the answer is e but how did it get that so work would be much appreciated.
A. x + y = 52
b. (x+y)^2=52
c. (x+y)^2=52^2
d. x^2+y^2=52
e. x^2+y^2=52^2
56. The transmitter site of radio station WGGW and the
transmitter site of another radio station, WGWB, are
on the same highway 100 miles apart. The radio signal
from the transmitter site of WGWB can be received
only within a radius of 60 miles in all directions from
the WGWB transmitter site. For how many miles along
the highway can the radio signals of both stations be
received? the answer is g but how did it get that so work would be much appreciated.
(Note: Assume the highway is straight.)
F. 8
G. 12
H. 40
J. 44
K. 48
so hope this helps and thank you for ur help as well as happy new year and merry christmas!

Answer by Alan3354(21550) About Me  (Show Source):
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The radio signal from the transmitter site of radio station WGGW can be received only within a radius of 52 miles in all directions from the transmitter site. A map of the region of coverage of the radio signal is shown be low in the
standard (x,y) coordinate plane, with the transmitter site at the origin and 1 coordinate unit representing 1 mile.
i don't know how to do a graph on here as there also is a graph to do these 3 problems. There is a circle, then a vertical and horizontal line crossing and where the intersect, there is like a 0 sort of. Then from that 0 to the y axis up is 52 and to the x axis on right is 52 too. So hope this helps, sorry i couldn't draw a graph for an easier way to do this problem.
54. Which of the following is closest to the area, in square miles, of the region of coverage of the radio signal? the answer is j but how did it get that so work would be much appreciated.
F. 2,120
G. 2,700
H. 4,250
J. 8,500
K. 16,990
It's the area of a circle with a radius of 52 miles.
Area+=+pi%2Ar%5E2+=+2704%2Api
=~ 8495 sq miles
----------------------
55. Whi ch of the fol lowing i s an equa t ion of the c i r c l e
shown on the map? the answer is e but how did it get that so work would be much appreciated.
A. x + y = 52
b. (x+y)^2=52
c. (x+y)^2=52^2
d. x^2+y^2=52
e. x^2+y^2=52^2
The eqn of a circle centered at (h,k) of radius r is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
For this one, h = k = 0
It's e
--------------------
56. The transmitter site of radio station WGGW and the
transmitter site of another radio station, WGWB, are
on the same highway 100 miles apart. The radio signal
from the transmitter site of WGWB can be received
only within a radius of 60 miles in all directions from
the WGWB transmitter site. For how many miles along
the highway can the radio signals of both stations be
received? the answer is g but how did it get that so work would be much appreciated.
(Note: Assume the highway is straight.)
F. 8
G. 12
H. 40
J. 44
K. 48
----------
If you draw the 2 circles, you'll see they overlap for 12 miles.
-------
dl the FREE graph software at
http://www.padowan.dk


Question 550005: Use synthetic division to determine which pair of integers provide both a lower and an upper bound for the zeros of f%28X%29=2X%5E4-X%5E3-23X%5E2%2B46X-24
Found 2 solutions by lwsshak3, stanbon:
Answer by lwsshak3(2907) About Me  (Show Source):
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f(X)=2X^4-X^3-23X^2+46X-24
**
Using the Rational Roots Theorem:
....0....|......2......-1......-23.......46.......-24
....1....|......2.......1.......-22.......24..........0 (1 is a root)
===========================
....0....|......2.......1.......-22.......24
....2....|......2.......5.......-12.......0 (2 is a root)
===========================
....0....|......2.......5.......-12
....3....|......2......11........21 (3 is upper bound-all numbers positive)
===========================
....0....|......2........5......-12
..-1....|......2........3......-15
..-2....|......2........1......-14
..-3....|......2......-1......-9
..-4....|......2......-3.......0 (-4 is a root)
===========================
....0....|......2......-3
..-5....|......2......-13 (-5 is lower bound-alternate sign of numbers)
f(x)=(x-1)(x-2)(x+4)(2x-3)
ans:
Upper bound and lower bound for zeros: x=3 and x=-5 respectivelly

Answer by stanbon(48510) About Me  (Show Source):
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f(X)=2X^4-X^3-23X^2+46X-24
----
The coefficients add up to zero, so x = 1 is a root:
-----
Use synthetic division to help find the 2 remaining roots:
1)...2....-1....-23.....46.....-24
......2.....1.....-22....24....|..0
-----------------------
Quotient: 2x^3+x^2-22x+24
------
I graphed the cubic and found a zero at x = 3/2
-------
(3/2))....2....1....-22....24
...........2....4.....-16...|0
----
Quotient: 2x^2+4x-16
---
Factor:
= 2(x^2+2x-8)
= 2(x+4)(x-2)
=====================
The roots are 1, 3/2 , 2 , -4
================================
Cheers,
Stan H.
=======================


Question 549506: What is the remainder when 2^1024 + 5^1024 +1 is divided by 9?
Answer by richard1234(4789) About Me  (Show Source):
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Several ways to do this. One way is to that

, and that

(modulo 9).

Similarly,

(modulo 9).

Hence the sum is equivalent to 7 + 4 + 1 = 12 = 3 (modulo 9), so the remainder is 3.


Question 549528: i am a two digit prime number the product of my digits is 24 what number am i?
Answer by mananth(10539) About Me  (Show Source):
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Factorize 24
24=2*2*2*3
split the factors into two terms
such that you get 24 on multuiplying them
3 & 8 OR 8 &3
83 is the number


Question 548318: a three digit number is divided by a 1 digit number the quotient is a 2 digit number what can you say about the dividend and the divisor ?
Answer by josmiceli(6769) About Me  (Show Source):
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xxx / x = xx
also,
xxx = xx * x
The 1-digit number can't be 1
If it is 2, then the 2-digit number
must be 50 or greater.
3-digit must be 100 or greater
------------------------
If it is 3, the 2-digit number must be
34 or greater. 3-digit is 102 - 297
--------------
If it is 4, the 2-digit number must be
25 or greater. 3-digit is 100 -396
--------------
If it is 5, the 2-digit number must be
20 or greater. 3-digit is 100 - 495
-------------
If it is 6, the 2-digit number must be
17 or greater. 3-digit is 102 - 594
-------------
If it is 7, the 2-digit number must be
15 or greater. 3-digit is 105 - 693
------------
If it is 8, the 2-digit number must be
13 or greater. 3-digit is 104 - 792
------------
If it is 9, the 2-digit number must be
12 or greater. 3-digit is 108 - 891


Question 547865: which prime numbers can make the number 90?
Found 2 solutions by Alan3354, JBarnum:
Answer by Alan3354(21550) About Me  (Show Source):
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90 = 7 + 83
= 11 + 79
= 17 + 73
= 19 + 71
= 23 + 67
= 29 + 61
= 31 + 59
= 37 + 53
= 43 + 47
-----------
And 1 + 89 if you want to count that.
I did positive only.
There's -7 + 97, etc, but prime number problems don't usually include negative numbers.

Answer by JBarnum(1826) About Me  (Show Source):
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3*3*2*5=90
so 2,3,5


Question 547381: what is divisble by both 3 and 4

Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(48510) About Me  (Show Source):
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what is divisible by both 3 and 4
Answer: 12

Answer by Alan3354(21550) About Me  (Show Source):
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All multiples of 12.


Question 547130: Divide:


x2
- x
+
3


x
+
1

Answer by JBarnum(1826) About Me  (Show Source):
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uh...im at a loss as to what this says anyone else have a clue my best guess is %28x%5E2-x%2B3%29%2F%28x%2B1%29%29 but i really cant tell why its vertical . i suggest you repost this with an accurate equation if you want help


Question 542569: What is 13/20 minus 1/5
9/20

Answer by deepa1999(1) About Me  (Show Source):
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13/20 - 1/5 =
13/20 - 4/20 = 9/20
13/20 - 1/5 = 9/20


Question 543190: Hi,
Kindly provide the solution for this below mentioned problem?
Find the largest 5-digit number which when divided by 84, 72 and 96 leaves remainder 82, 70, and 94 respectively.
Regards
Gopinath

Answer by KMST(576) About Me  (Show Source):
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The key to solving this problem is to realize that your mystery number is 2 short of a multiple of 84, 72, and 96. If we call your mystery number n, then n%2B2 is a multiple of 84, 72, and 96.
84=7%2A12=2%5E2%2A3%2A7
72=8%2A9=2%5E3%2A3%5E2
96=32%2A3=2%5E5%2A3%5E2
The least common multiple of 84, 72, and 96 is
LCM%2884%2C72%2C96%29=2%5E5%2A3%5E3%2A7=96%2A7=672
If the problem just asked for any "number which when divided by 84, 72 and 96 leaves remainder 82, 70, and 94 respectively," we would say that n%2B2=672, with n=670 would be one of many solutions. All the solutions would be numbers such that
n%2B2=672%2Ak for some positive integer k.
As the problem asks for "the largest 5-digit number," we need to look for an n%2B2 multiple of 672 that makes n the largest 5-digit number complying with the condition.
10%5E5%2F672=about148.8 according to my calculator, so I can easily estimate that n%2B2=148%2A672 will yield a 5-digit n, while the next larger multiple of 672 n%2B2=149%2A672 will yield a 6-digit n
In other words, n=148%2A672-2=99454 is the solution.


Question 542072: I am a number less than 40. One of my factors is 7. the sum of my digits is 8. what number am I?
Answer by Edwin McCravy(6931) About Me  (Show Source):
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I am a number less than 40. One of my factors is 7. the sum of my digits is 8. what number am I?
Two ways to figure out what number you are:

First way:
The numbers less that 40 which have sum of digits 8 are 17, 26, 35.
Only one of those that has a factor of 7.  And that is 35.  
So you are 35.

Second way:
The numbers less that 40 which have a factor of 7 are 7,14,21,28,35
Only one of those which has sum of digits as 8.  And that is 35.
So you are 35.

Edwin



Question 511955: what is the product of the greatest and least two digit prime number
Answer by octogirl(6) About Me  (Show Source):
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the smallest two digit prime numbeer is 11 and the biggest is 97 mutiply that you get 1067 as your answer


Question 486539: 999 +9
Answer by octogirl(6) About Me  (Show Source):
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1008 is the answer.


Question 539753: what are the divisible numbers to 2367

Found 2 solutions by KMST, AnlytcPhil:
Answer by KMST(576) About Me  (Show Source):
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What are the factors of 2367? The numbers that divide 2367 evenly? The divisors of 2367?
Since the digits add up to a multiple of 9 (3+6=9 and 2+7=9), 2367 is divisible by 9. When we divide it by 9, we get 263.
We look for prime numbers that will be divisors of 263.
It's not even, so 2 does not work.
It is not divisible by 3, because the digits do not add to a multiple of 3 (2+6+3=11).
If does not end in 5 or 0, so it's not divisible by 5.
The next prime number is 7, and my calculator says 263 divided by 7 is not a whole number.
The next prime number is 11, and does not work either. (There is an easy test for divisibility by 11, and 263 does not pass that test).
The next prime number is 13, and my calculator says that 263 divided by 13 is not a whole number either.
The next prime number is 17, but 17%5E2=289%3E263 and that tells me I should stop here.
If 263 was 17 times some other number, that other number would have to be smaller than 17. If not prime, it would have a smaller prime divisor that should also divide 263. However, we could not find any prime divisor for 263 below 17, so 263 is a prime number.
2367=9%2A263=3%2A3%2A263 The prime factorization of 2367 is 2367=3%5E2%2A263
The factors (divisors) of 2367, in pairs are
1 and 2367 2637=1*2367
3 and 7101 2367=3*7107=3*3*263
9 and 263 2367=9*263

Answer by AnlytcPhil(1116) About Me  (Show Source):
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2367 = 3×3×263
Its divisors are 1, 3, 9, 263, 789, and 2367


Question 538998: find the prime fractorization of 180

Answer by fcabanski(385) About Me  (Show Source):
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Divide by prime numbers until you've found all the prime numbers that, when multiplied together, equal 180.


It's best to begin by dividing by the lowest possible prime. It's even, so divide by 2.


180/2 = 90. So the first prime factor is 2.


90/2 = 45. Prime factors so far (2*2)


45/5 = 9. Prime factors so far (2*2*5)


9/3=3. 3 is a prime number so that gives 3*3.


Prime factorization of 180 is 2*2*3*3*5

If you need help understanding math so you can solve these problems yourself, then one on one online tutoring is the answer ($30/hr). If you need faster solutions with guaranteed detailed answers, then go with personal problem solving ($3.50-$5.50 per problem). Contact me at fcabanski@hotmail.com




Question 537866: Hello...can you tell me the anser to 49 divided by 4,255
Answer by fcabanski(385) About Me  (Show Source):
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A calculator can show you that answer.


.0115158636...


To solve it with long division add a decimal after 49, and as many 0's as necessary.

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