SOLUTION: The center of an ellipse is the point (-4, 2) and one vertex is at (1, 2). The length of each latus rectum is 4. Find the eccentricity.
Algebra.Com
Question 886570: The center of an ellipse is the point (-4, 2) and one vertex is at (1, 2). The length of each latus rectum is 4. Find the eccentricity.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
The center of an ellipse is the point (-4, 2) and one vertex is at (1, 2). The length of each latus rectum is 4. Find the eccentricity.
***
Given data shows ellipse has a horizontal major axis.
Its standard form of equation: ,a>b, (h,k)=coordinates of center
1/2 length of major axis=5 (center to vertex)
a=5
a^2=25
latus rectum=2b^2/a=4
4a=2b^2
b^2=2a=10
c^2=a^2-b^2=25-10=15
c=√15
eccentricity=c/a=√15/5
RELATED QUESTIONS
The center of an ellipse is on (-2, -1) and one of its vertex is on (3, -1). It the... (answered by MathLover1)
Find the equation of parabola with vertex at (4, 2), latus rectum 20, and opens... (answered by greenestamps)
The length of the latus rectum for the ellipse (x^2/64) + (y^2/16) = 1 is equal to:
a)2
(answered by lwsshak3)
Find the foci, eccentricity, length of latus rectum, and the x and y intercepts of the... (answered by MathLover1)
Need this problems solution...
Find the equation of the parabola whose vertex is at... (answered by lwsshak3)
with axis x=-2, length of the latus rectum = 6, and passing through (4,8). find the... (answered by lwsshak3)
find the general equation of ellipse with center at (1,5), major axis parallel to... (answered by Edwin McCravy)
Find the vertices, foci, eccentricity, and length of the latus rectum of the ellipse... (answered by lwsshak3)
Find the equation of the hyperbola with center at (4,-1) transverse axis parallel to the... (answered by Edwin McCravy)