SOLUTION: please help me to solve the following 0.3(x - 4) = 0.03(4x - 8) thanks

Algebra.Com
Question 63734This question is from textbook An Incremental Development
: please help me to solve the following
0.3(x - 4) = 0.03(4x - 8)
thanks
This question is from textbook An Incremental Development

Answer by praseenakos@yahoo.com(507)   (Show Source): You can put this solution on YOUR website!
QUESTION:
solve the following
0.3(x - 4) = 0.03(4x - 8)


ANSWER:

0.3(x - 4) = 0.03(4x - 8)


Remove the brackets by multiplying term by term.

==> 0.3(x - 4) = 0.03(4x - 8)


==> 0.3 * x - 0.3 * 4 = 0.03 * 4x - 0.03 * 8


==> 0.3x - 1.2 = 0.12x - 0.24


collect like terms together,(That is x terms and constant terms seperately)

For that,


0.3x - 1.2 = 0.12x - 0.24


add 1.2 on both sides. (FOR COLLECTING CONSTANT TERMS)


==> 0.3x - 1.2 + 1.2 = 0.12x - 0.24 + 1.2


==> 0.3x = 0.12x + 9.6


Subtract 0.12x from both sides. (FOR COLLECTING X TERMS TOGETHER)


==> 0.3x -0.12x = 0.12x + 9.6 - 0.12x


==> 0.18 x = 9.6


Divide both sides by 0.18


==> 0.18 x / 0.18= 9.6/0.18


==> X = 5.333333



SO, x = 5.33



Regards.
praseenakos@yahoo.co.in




RELATED QUESTIONS

Solve a) x^3-x^2-4x+4=0 b) x^3-4x^2+x+6=0 c) x^3-x^2-3x+6=0 d) x^4-3x^3-2x^2+12x-8=0 (answered by Alan3354)
Please help with the following: Use the quadratic formula to solve the quadratic... (answered by adamchapman)
Please help me with the following: The following data were obtained from a survey of... (answered by jim_thompson5910)
Solve a) x^3-x^2-4x+4=0 can you please help me? thanks so much in... (answered by stanbon)
Please help me with the following problem Solve the equation 1/2x2 -4x +8 = 0 this (answered by stanbon)
Solve a) x^3-x^2-4x+4=0 b) x^3-4x^2+x+6=0 c) x^3-x^2-3x+6=0 d) x^4-3x^3-2x^2+12x-8=0 (answered by Alan3354)
Please help me solve this x^2-4x(-4)=... (answered by jim_thompson5910)
please help me solve the following equation 7x^(2)+4x-3=0 (answered by algebrahouse.com)
Hello how do I solve X^4-X^3+2X^2-4x-8=0 Using the real number system? Please... (answered by Alan3354)