Let ln(x) = y. 3y^3 - 4y^2 - 5y + 2 = 0 (y - 2)(3y - 1)(y + 1) = 0 y = 2, y = 1/3, or y = -1 Consider all three cases separately. 1) ln(x) = 2 ----> x = e^2. 2) ln(x) = 1/3 ----> x = e^(1/3) = . 3) ln(x) = -1 ----> x = e^(-1) = 1/e.