SOLUTION: my number is 25.3 divided by a number with 1 decimal digit it gives me a quotient greater than 10 but less than 11 what is my number?

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Question 1204109: my number is 25.3 divided by a number with 1 decimal digit it gives me a quotient greater than 10 but less than 11 what is my number?
Found 3 solutions by math_tutor2020, greenestamps, Edwin McCravy:
Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

x = the number you are dividing over
It must be a positive number so that is between the two positive numbers 10 and 11.



Multiply all three sides by x. Multiplying all sides by a positive number does not flip the inequality signs.



That last inequality breaks down into these two inequalities
and

Solve to get

Solve to get aka


We found that and .
Glue those together to get


Here's a table of examples
x(25.3)/xResult greater than 10 but less than 11?
2.2811.0965no
2.311no
2.3210.9052yes
2.3410.812yes
2.3610.7203yes
2.3810.6303yes
2.410.5417yes
2.4210.4545yes
2.4410.3689yes
2.4610.2846yes
2.4810.2016yes
2.510.12yes
2.5210.0397yes
2.549.9606no

With the exception of the results 11 and 10.12, each of the values in the 2nd column are approximate.

If we rounded to one decimal place, then the only possible x solutions would be: x = 2.4 and x = 2.5

x = 2.3 doesn't work since becomes and then simplifies to which is false.

But x = 2.4 does work
becomes and then simplifies to which is true

x = 2.5 also works as well
becomes and then simplifies to which is true.



Answer: The mystery number is either 2.4 or 2.5

Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!


Let x be the number we are looking for.

From the given information, we know the number is positive, so...

-->

and

-->

So x is greater than 2.3 and less than 2.53. Since we are told that the number has one decimal place, the number can be either 2.4 or 2.5

ANSWER: either 2.4 or 2.5


Answer by Edwin McCravy(20061)   (Show Source): You can put this solution on YOUR website!

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