SOLUTION: Find max/min when x belongs to the interval (0,infinite sign)
For function:
f (x) = (lnx)^2 - 3lnx
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Question 1035333: Find max/min when x belongs to the interval (0,infinite sign)
For function:
f (x) = (lnx)^2 - 3lnx
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
==> .
Now find the critical points of the function by letting
==> , or or .
Now apply the first derivative test:
When , ==> f(x) is increasing over there.
When , ==> f(x) is decreasing over there.
Thus there is a local minimum at , and since it is the only critical point in an open interval (0, ), it is also an absolute minimum.
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