# SOLUTION: I am very lost with this problem. Here it is: Arnie Waldman has chosen a workout that combines weight training and aerobics. If he does 30 min of weight training, followed by a 30-

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I am very lost with this problem. Here it is: Arnie Waldman has chosen a workout that combines weight training and aerobics. If he does 30 min of weight training, followed by a 30-      Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Mathway solves algebra homework problems with step-by-step help!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 219604: I am very lost with this problem. Here it is: Arnie Waldman has chosen a workout that combines weight training and aerobics. If he does 30 min of weight training, followed by a 30-min aerobics class, he will burn a total of 374 calories. If he burns 12/5 as many calories doing aerobis as doing weight traing, how many calories will he burn in each activity?Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Arnie Waldman has chosen a workout that combines weight training and aerobics. If he does 30 min of weight training, followed by a 30-min aerobics class, he will burn a total of 374 calories. If he burns 12/5 as many calories doing aerobis as doing weight traing, how many calories will he burn in each activity? ----------------------- weight training calories: x aerobic calories::::::::: (12/5)x --------------------------------------- Equation: x + (12/5)x = 374 Multiply thru by 5 to get: 5x + 12x = 5*374 17x = 5*374 x = 110 calories (from weight training) ---- (12/5)x = 264 calories (from aerobics) =========================================== Cheers, Stan H.