SOLUTION: A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station

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Question 994849: A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet?
Found 2 solutions by lwsshak3, josgarithmetic:
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
A train leaves a station and travels north at a speed of 30 mph. Five hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet?
let x=travel time of 2nd train
x+5=travel time of 1st train
distance=travel time*speed
30(x+5)=105x
30x+150=105x
75x=150
x=2
105x=30(x+5)=210
How far from the station will they meet? 210 mi
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
A very common type of travel rates exercise problem. This will be a general solution for just that reason. 
r      speed of early, slow train
R      speed of fast, late train
t      travel time for fast train, left later than slow train
h      amount of time passed before fast train departed
d      the catch-up distance


TRAIN         speed       time     distance
Early Slow      r         t+h       d
Late Fast       R         t         d

Question is to solve for d.
The unknown variables are t and d, but you do not need to find a value for t. (Unless you WANT to).
Initial system of equations,

-









---The answer in symbolic form.

Your question gives you the values to use:
Substitute these and evaluate d:
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