SOLUTION: A researcher has a testing pot used for testing seeds. The perimeter of the plot is 322m. The length of the plot is 25m more than the width. Find the dimensions of the plot.

Question 987512: A researcher has a testing pot used for testing seeds. The perimeter of the plot is 322m. The length of the plot is 25m more than the width. Find the dimensions of the plot.
Found 2 solutions by algebrahouse.com, lwsshak3:
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
w = width
w + 25 = length {length is 25 more than the width}

Perimeter of a rectangle = 2(width) + 2(length)

2w + 2(w + 25) = 322 {substituted width and length into perimeter formula}
2w + 2w + 50 = 322 {used distributive property}
4w + 50 = 322 {combined like terms}
4w = 272 {subtracted 50 from each side}
w = 68 {divided each side by 4}
w + 25 = 93 {substituted 68, in for w, into w + 25}

width = 68 m
length = 93 m

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Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
researcher has a testing pot used for testing seeds. The perimeter of the plot is 322m. The length of the plot is 25m more than the width. Find the dimensions of the plot.
let x=width
x+25=length
2(width+length)=perimeter
2x+2(x+25)=322
2x+2x+50=322
4x=272
x=68
width=68m
length=93 m
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